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CarlaG
#1 Posted : Tuesday, December 2, 2014 9:29:18 AM
Rank: Member

Groups: Registered

Joined: 5/29/2007
Posts: 8
Hi,

We are using Search for ASP.NET 2012 version 2012.5.14.423. We are sometimes getting this error message:

Page location: /searchresults.aspx?queryexpr=new+online+training&resultspage=1

Message: Index was out of range. Must be non-negative and less than the size of the collection.
Parameter name: startIndex

Source: mscorlib

Method: Int32 IndexOf(Char, Int32, Int32)

Stack Trace:

at System.String.IndexOf(Char value, Int32 startIndex, Int32 count)
at Keyoti.SearchEngine.Web.SearchSuggestions.RenderContents(HtmlTextWriter output)
at System.Web.UI.WebControls.WebControl.Render(HtmlTextWriter writer)
at System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter)
at System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children)
at System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter)
at ASP.app_master_onecolumn_master.__Renderform1(HtmlTextWriter __w, Control parameterContainer)
at System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children)
at System.Web.UI.HtmlControls.HtmlForm.RenderChildren(HtmlTextWriter writer)
at System.Web.UI.HtmlControls.HtmlContainerControl.Render(HtmlTextWriter writer)
at System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter)
at System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children)
at System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter)
at System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children)
at System.Web.UI.Page.Render(HtmlTextWriter writer)
at System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter)
at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint)

Do you know what can be causing this error?

Thank You
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